Question

10^-2 mole of KOH is dissolved in 10 litres the pH of solution

Answer 1

ph=12

It doesn't matter unless you dissolve it in a chemical which releases either H+ or OH-. Because of release if H+ or OH- the net concentration increase of either of these which accounts for the increase or decrease in net ph. Although water also breaks down into H+ and OH- but the OH- release form the KOH combines with the H+ from water and an equal amount of OH- from water remains free. So

$poh = - log(oh) \\ \: \: \: \: \: \: \: \: = - log(10^{ - 2} ) \\ \: \: \: \: \: \: \: \: = 2$

ph=14-poh

=14-2

=12