Physics, asked by rishireddy1104, 1 year ago

10*π*(25*10^-5)^2 whole divided by / 1.6*10^-8

Answers

Answered by prathmeshmalewar007
0

=(10×π×25×10^-5×25×10^-5)/(1.6×10^-8)

=(10×π×625×10^-10)/(1.6×10^-8)

= 6.25×π×625×10^-2

=6.25×6.25×π

=39.0625π = 122.65 (approx.)

Hope it helps, feel free to mark as brainlliest...


rishireddy1104: Can u explain the 3rd step plz
prathmeshmalewar007: Cancelled out numerators 10^-10 by denominators 10^-8, so it leaves u with 10^-2 in numerator
Answered by ariestheracer
0

 \frac{ 10 \times \pi \times (25 \times  {10}^{ - 5} )^{2} }{1.6 \times  {10}^{ - 8} }

 =  >  \frac{10\pi \times (25 \times  {10}^{ - 5}) ^{2}  }{1.6 \times  {10}^{ - 8} }

 =   \frac{ {10}^{9} \pi \times \: 625  \times  {10}^{ - 10} }{ \frac{8}{5} }

 =  \frac{3125 \times  {10}^{ - 1}\pi }{8}

 =  \frac{3125\pi}{8  \times 10}

 =  \frac{625\pi}{8 \times 10}

 =  \frac{625\pi}{16}

Alternative Form:-

 \frac{28125}{4}  = 122.71845

If not understand attachment is given above..

hope this helps you...

Attachments:

rishireddy1104: I didn't get the third step
ariestheracer: in second step you have seen the denominator that is 8/5
ariestheracer: so express it into simpler form.
ariestheracer: take 5 above and multiply 625 × 5 which is equal to 3125 and subtract 10^9 pi - 10^(-9) which is equals to 10 ^(-1) pi
ariestheracer: now it's clear..??
ariestheracer: ??
ariestheracer: hope it's clear..??
rishireddy1104: Yeah
ariestheracer: cool..!!!
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