Question

____+ 10+25 (Find the first term)
$4x {}^{2} + 12 + - - - - - \\ find \: the \: last \: term$
$4x {}^{2} + - - - - + 1 \\ find \: the \: middle \: term \:$
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Answer 1

Answer:

SOLUTION :

\begin{gathered}the \: given \: series \: is \: in \: ap \\ \\ common \: difference \: (d) = a2 - a1 = 2 \\ \\first \: term(a) \: = 5 \\ \\ 5th \: term \: of \: ap = a + 4d = 5 + 4(2) = 13 \\ \\ 6th \: term \: of \: ap = a + 5d = 15 \\ \\ 7th \: term \: of \: ap = a + 6d = 17 \\ \\ 8th \: term \: of \: ap = a + 7d = 19\end{gathered}

thegivenseriesisinap

commondifference(d)=a2−a1=2

firstterm(a)=5

5thtermofap=a+4d=5+4(2)=13

6thtermofap=a+5d=15

7thtermofap=a+6d=17

8thtermofap=a+7d=19

∴ THE NEXT FOUR TERMS OF THE GIVEN AP IS 13 , 15 , 17 , 19