Math, asked by praveenkr2k9, 5 months ago


10. 25 squares each of perimeter 8 cm are placed adjacent to each other to form a rectangle of
length 50 cm. What is the area of the rectangle formed? ​

Answers

Answered by dhairyamharidwar
2

Step-by-step explanation:

Perimeter of square = 8

side=8/4 = 2

L=50cm

B=2cm

A= L*B

==50*2

==100 cm^2

Answered by supernovalegend
3

Answer:

Step-by-step explanation:

4* side = perimeter of a Square

4*side = 8

Each side = 8/4 = 2cm

Area of a Square =side x Side

Area = 2x2 =4 =4 cm^2

There are 25 squares

Total area =25 x4 =100

= 100 cm ^2

The area of the rectangle = 100 cm^2

Rectangle length = 50 cm

Breadth = 2cm ( one side of square)

Area of rectangle is length x Breadth = 50 x 2 = 100 cm^2

= 100 cm^2

Therefore your answer is 100 cm^2

"Thank you"

Similar questions