Physics, asked by uttkarshkhanke, 5 months ago

10) (2i+3j-k) (2i+3j-k) =
a) 0 = 0
b) 0 = 30
c) 0 = 60
d) 0 = 90​

Answers

Answered by omibadrakhiya
2

Answer:

0=0

Explanation:

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