10.2root3+ root 3 is equal to
(A) 2/6 (B) 6
(0) 33
(D)
4/6
Answers
Answered by
0
Answer:
10
+
3
7
3
−
6
+
5
2
5
−
15
+3
2
3
2
Rationalizing this equation, we get
=\frac{7\sqrt{3}(\sqrt{10}-\sqrt{3})}{10-3}-\frac{2\sqrt{5}(\sqrt{6}-\sqrt{5})}{6-5}-\frac{3\sqrt{2}(\sqrt{15}-3\sqrt{2})}{15-18}
10−3
7
3
(
10
−
3
)
−
6−5
2
5
(
6
−
5
)
−
15−18
3
2
(
15
−3
2
)
=\sqrt{3}(\sqrt{10}-\sqrt{3})-2\sqrt{5}(\sqrt{6}-\sqrt{5})+\sqrt{2}(\sqrt{15}-3\sqrt{2})
3
(
10
−
3
)−2
5
(
6
−
5
)+
2
(
15
−3
2
)
=\sqrt{30}-3-2\sqrt{30}+10+\sqrt{30}-6
30
−3−2
30
+10+
30
−6
=11
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