Question

10(2x+3)-8(3x-5)+5(2x-8)=0 ???

Answer 1

Simplifying 10(2x + 3) + -8(3x + -5) + 5(2x + -8) = 0 Reorder the terms: 10(3 + 2x) + -8(3x + -5) + 5(2x + -8) = 0 (3 * 10 + 2x * 10) + -8(3x + -5) + 5(2x + -8) = 0 (30 + 20x) + -8(3x + -5) + 5(2x + -8) = 0 Reorder the terms: 30 + 20x + -8(-5 + 3x) + 5(2x + -8) = 0 30 + 20x + (-5 * -8 + 3x * -8) + 5(2x + -8) = 0 30 + 20x + (40 + -24x) + 5(2x + -8) = 0 Reorder the terms: 30 + 20x + 40 + -24x + 5(-8 + 2x) = 0 30 + 20x + 40 + -24x + (-8 * 5 + 2x * 5) = 0 30 + 20x + 40 + -24x + (-40 + 10x) = 0 Reorder the terms: 30 + 40 + -40 + 20x + -24x + 10x = 0 Combine like terms: 30 + 40 = 70 70 + -40 + 20x + -24x + 10x = 0 Combine like terms: 70 + -40 = 30 30 + 20x + -24x + 10x = 0 Combine like terms: 20x + -24x = -4x 30 + -4x + 10x = 0 Combine like terms: -4x + 10x = 6x 30 + 6x = 0 Solving 30 + 6x = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-30' to each side of the equation. 30 + -30 + 6x = 0 + -30 Combine like terms: 30 + -30 = 0 0 + 6x = 0 + -30 6x = 0 + -30 Combine like terms: 0 + -30 = -30 6x = -30 Divide each side by '6'. x = -5 Simplifying x = -5