10^2y =25 ; find 10^-y+1
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10^2y = 25
[using a^mn = ((a)^m)^n]
((10)^y)^2 = 25
10^y = sqrt(25) = 5
10^-y + 1
[Using a^-m = 1/(a^m)]
= (1/(10)^y) + 1
= (1/5) + 1
= 6/5 ——> Answer
[using a^mn = ((a)^m)^n]
((10)^y)^2 = 25
10^y = sqrt(25) = 5
10^-y + 1
[Using a^-m = 1/(a^m)]
= (1/(10)^y) + 1
= (1/5) + 1
= 6/5 ——> Answer
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