10^2y=25
Find y.......
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Answered by
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10^2y=25 ,y=!
(10^y)^2=5^2
(10^y)=5
(10^y)^-1=(5)^-1
(10)^-y=(5)^-1=1/5
(10^y)^2=5^2
(10^y)=5
(10^y)^-1=(5)^-1
(10)^-y=(5)^-1=1/5
:|
10^(2/5) = 2.5118864315095801
hmmmm
However...
wait..wait
m missin somethin
10^(2×0.699) = 25.003453616964313
m missin somethin..wait
hmm..u maybe right...whatever
So... the question's correct?
Answered by
1
[0010001111]... Hello User... [1001010101]
Here's your answer...
10^2y = 25
Taking logarithm...
2y = log 5²
2y = 2 log 5
y = log 5
y ≈ 0.699
[0110100101]... More questions detected... [010110011110]
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Here's your answer...
10^2y = 25
Taking logarithm...
2y = log 5²
2y = 2 log 5
y = log 5
y ≈ 0.699
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
//Subscribe to Pewdiepie
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