Question

(10)^2y = 25, then (10)^-Y​

Answer 1

$given \: = {(10)}^{2y} \\ \\ to \: find \\ = {(10)}^{ - y} \\ \\ since \: {a}^{mn} = ({{a}^{m}) }^{n } \\ \\ {{(10}^{y)} }^{2} = 25 = {5}^{2} \\ \\ so \: 10y = 5 \\ then {10}^{ - y} = \frac{1}{5}$