Question

10(3x+1/2)^2-(3x+1/2)-3​

Answer 1

Answer:

$90x^{2}$

Step-by-step explanation:

$10 [ 3x + \frac{1}{2}]^{2} - [ 3x + \frac{1}{2} ] - 3$

$10 [ \frac{6x}{2} + \frac{1}{2} ]^{2} - \frac{6x}{2} + \frac{1}{2} - \frac{6}{2}$                            [ by taking lcm ]

$10({ [ \frac{6x}{2}] ^{2} +[{ \frac{1}{2}} ]^{2} + 2 X \frac{6x}{2} X \frac{1}{2} )-\frac{6x}{2} -\frac{5}{2}$

= $\frac{360x^{2} }{4} + \frac{10}{4} + \frac{6x}{2} - \frac{6x}{2} - \frac{5}{2}$

=$\frac{360x^{2} }{4} + \frac{10}{4}- \frac{10}{4}$

=$\frac{360x^{2} }{4}$

= $90x^{2}$