(10-3x) (10+3x) factorise
Answers
Answered by
0
Answer:
1
Rearrange terms
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({\color{#c92786}{10-3x}})(10+3x)
(10−3x)(10+3x)
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({\color{#c92786}{-3x+10}})(10+3x)
(−3x+10)(10+3x)
2
Rearrange terms
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−
3
+
1
0
)
(
1
0
+
3
)
(-3x+10)({\color{#c92786}{10+3x}})
(−3x+10)(10+3x)
(
−
3
+
1
0
)
(
3
+
1
0
)
(-3x+10)({\color{#c92786}{3x+10}})
(−3x+10)(3x+10)
3
Distribute
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{\color{#c92786}{(-3x+10)(3x+10)}}
(−3x+10)(3x+10)
−
3
(
3
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0
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+
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)
Answered by
1
Answer:
10²-3x²
Step-by-step explanation:
Using identity ,
(a-b) (a+b) = a²-b²
(10-3x) (10+3x) = 10²-3x²
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