10−[4xy+3{x2−(xy−y)−(x−y+1)}]
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Given:
10 - [ 4xy + 3 { x^2 - ( xy - y ) - ( x - y + 1 ) } ]
To find:
We have to find the simplified form of the given term
Step-by-step explanation:
Now, 10 - [ 4xy + 3 { x^2 - ( xy - y ) - ( x - y + 1 ) } ]
= 10 - [ 4xy + 3 { x^2 - xy + y - x + y - 1 } ]
= 10 - [ 4xy + 3 { x^2 - xy + 2y - x - 1 } ]
= 10 - [ 4xy + 3x^2 - 3xy + 6y - 3x - 3 ]
= 10 - [ xy + 3x^2 + 6y - 3x - 3 ]
= 10 - xy - 3x^2 - 6y + 3x + 3
= 13 - xy - 3x^2 - 6y + 3x
This is the required simplified form.
To remember:
While simplifying the given term, we have used BODMAS rule, where B stands for brackets, O stands for order, D stands for division, M stands for multiplication, A stands for addition and S stands for subtraction.
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