Math, asked by KajalRukhamode, 9 months ago

10-[5(1+x)/3]+3x+1/5=0
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Answers

Answered by tummakeerthana19
1

Answer:

10-(5(1+x)/3)+3x+1/5=0

10-(5+5x/3)+3x+1/5=0

30-5+5x/3+3x+1/5=0

25-5x/3 +3x+1/5=0

25-5x+9x/3 +1/5=0

25+4x/3 +1/5=0

125+3+4x/15=0

128+4x/15=0

128+4x=0

4x=-128

x=-128/4=-32

therefore x=-32

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Answered by akshaykotha665
0

.....hope u understand..

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