10-[5(1+x)/3]+3x+1/5=0
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10-(5(1+x)/3)+3x+1/5=0
10-(5+5x/3)+3x+1/5=0
30-5+5x/3+3x+1/5=0
25-5x/3 +3x+1/5=0
25-5x+9x/3 +1/5=0
25+4x/3 +1/5=0
125+3+4x/15=0
128+4x/15=0
128+4x=0
4x=-128
x=-128/4=-32
therefore x=-32
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