Question

10
5
Question 2
Solve the equations:
(a?) 3(x - 1) + 7 = 11
(b) 14 = - 8
(r-3)
(c?)
2 = -1
(d) 20 (2.x - 5) = 25
(-7)
-1=0
() - 7 = 3
(g) 32 + 11 = 41
(h) 4 r + 1) = 16
(0) 2.x + J = 7
(0) 4 (x + 1) = 4
(e)
3​

Answer 1

Answer:

(a)sol.3(x-1)+7=11

L.H.S.=R.H.S.

3x-3+7=11

3x+4=11

3x=11-4

3x=7

x=7/3