Question

10. 50 students of a class like either oranges or grapes or both. 20 of them like oranges, while
10 like both. Draw a Venn diagram and find how many like (i) only oranges. (11) grapes,
(iii) only grapes?​

Answer 1

Let M= The set of students passed in Mathematics

S= The set of students passed in Science

Then, n(S)=28,n(M∩S)=10,n(M∪S)=50

We have n(M∪S)=n(M)+n(S)−n(M∩S)

50=n(M)+28−10

⇒n(M)=32

Aliter

From the Venn diagram

x+10+18=50

x=50−28=22

Number of students passed in Mathematics =x+10=22+10=32

solution