Question

10-5i/6+2i in the form of a+ib​

Answer 1

Answer:

5%2F%286-2i%29

%285%2F%286-2i%29%29%28%286%2B2i%29%2F%286%2B2i%29%29Multiply both top and bottom by the complex conjugate of 6-2i

%285%2A%286%2B2i%29%29%2F%2836%2B12i-12i-4%28-1%29%29FOIL the denominator (remember i%5E2=-1)

%285%2A%286%2B2i%29%29%2F%2836%2Bcross%2812i-12i%29-4%28-1%29%29The i terms cancel in the denominator

%285%2A%286%2B2i%29%29%2F%2840%29%29Distribute the 5 among the parenthesis

%2830%2B10i%29%2F%2840%29%29

30%2F40%2B%2810%2F40%29i

3%2F4%2B%281%2F4%29iHere's the answer in a+bi form where a=3/4 and b=1/4