Question

10×6-[5+{10-(5-2)}3]​

Answer 1

Answer:

Step-by-step explanation:

apply BODMAS Breacket , off ,divison,multiplication,add,subtract

Q-  10 × 6 - [ 5 + { 10 - ( 5-2 ) } 3 ]

60 - [ 5 + { 10 - 3 } 3 ]

60 - [ 5 + { 7 } 3 ]

60 - [ 5 + 7 × 3 ]

60 - [ 5 + 26 ]

60 - ( 31 )

60 - 31= 29 is the answer

hope it helps

Answer 2

Answer:

Required answer is 34.

Step-by-step explanation:

Given,10×6-[5+{10-(5-2)}3]

We want to simplify it.

By BODMAS rule, we can solve this problem.

By BODMAS rule,

Bracket -Of - Division - Multiplication - Addition - Subtraction

So,10×6-[5+{10-(5-2)}3]

= 10×6-[5+{10-3}3]

= 10×6-[5+7×3]

= 10×6-[5+21]

= 10×6-26

=10×6-26

=60-26

=34

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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