Question

10). 6) A wooden box of dimensions as I =20 cm, b = 25 cm & h= 10 cm is
lying on the ground. If the mass of box is 50 kg, find the pressure exerted
when it is resting with the area of contact as -a) 20cm x10cmb)
20cmx25cmc) 25cmx10cm. Given g = 10m/s2​

Answer 1

Answer:

25000pa, 10000pa, 20000pa

Explanation:

from here

volume of the box = l* b * h

so v= 20cm*25*cm * 10 cm

v=5000cm^3

v= 0.005m^3

we know

density = m/v

so , d= 50/0.005

d= 10000kg/ m^3

now pressure when a= 20*10

p= f/a

p= mg/0.02

p= 25000 pa

when area =20*25

p= f/ a

p= mg/0.05

p= 10000 pa

when area = 25 *10

p= f/ a

p= mg/ 0.025

p= 20000pa

p=