Question

10^6 electron are moving from a to B in 10 second. Same time number of proton are moving from B to a in 20 second. Find the current.
Class 10th question​

Answer 1

Explanation:

HOPE IT HELPS YOU

Answer 2

$\frac{ 10 ^ { 6 } \times 1.6 \times 10 ^ { -19 } }{ 10 } + \frac{ 10 ^ { 6 ^ { } } \times 1.6 \times 10 ^ { 19 } }{ 20 } \\ \\ \sf \: To \: multiply \: powers \: of \: the \: same \: base, \: add \: their \: exponents. \\ \sf \: Add \: 6 \: and \: -19 \: to \: get \: -13 \\ \\ \\ ⇛ \sf \: \frac{10^{-13}\times 1.6}{10}+\frac{10^{6^{1}}\times 1.6\times 10^{19}}{20} \\ \\ \\ \sf \: Calculate \: 10 \: to \: the \: power \: of \: -13 \: and \: get \: \frac{1}{10000000000000} \\ \\ \\ ⇛ \sf \: \frac{\frac{1}{10000000000000}\times 1.6}{10}+\frac{10^{6^{1}}\times 1.6\times 10^{19}}{20} \\ \\ \\⇛ \sf \: Multiply \: \frac{1}{10000000000000} and 1.6 to get \frac{1}{6250000000000} \\ \\ \\⇛ \sf \: \frac{\frac{1}{6250000000000}}{10}+\frac{10^{6^{1}}\times 1.6\times 10^{19}}{20} \\ \\ \\ ⇛\sf \: \frac{1}{6250000000000\times 10}+\frac{10^{6^{1}}\times 1.6\times 10^{19}}{20} \\ \\ \\⇛ \sf \: \frac{1}{62500000000000}+\frac{10^{6^{1}}\times 1.6\times 10^{19}}{20} \\ \\ \\ ⇛\sf \: \frac{1}{62500000000000}+\frac{10^{6}\times 1.6\times 10^{19}}{20} </p><p> \\ \\ \\ ⇛ \sf \: \frac{1}{62500000000000}+\frac{1000000\times 1.6\times 10^{19}}{20} \\ \\ \\ ⇛ \sf \: \frac{1}{62500000000000} + \frac{1600000\times 10^{19}}{20} \\ \\ \\ ⇛ \sf \: \frac{1}{62500000000000}+\frac{1600000\times 10000000000000000000}{20} \\ \\ \\ ⇛\sf \: \frac{1}{62500000000000} + \frac{16000000000000000000000000}{20} \\ \\ \\ ⇛\sf \: \frac{1}{62500000000000}+800000000000000000000000 \\ \\ \\ \sf \: Add \: \frac{1}{62500000000000} \: and \: 800000000000000000000000 \: to \: get \\ \\ \sf \: \frac{50000000000000000000000000000000000001}{62500000000000}\\ \\ \\ \sf \:⇛\frac{50000000000000000000000000000000000001}{62500000000000} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \huge \sf{@WildCat7083 }$