Question

10^6 electrons are moving through a wire per second, the current developed is?

Solution??

Answer 1

i =q/t

so

q=10^6*1.6*10^-19

t=1s

i=1.6 *10^10^-13 ampere

Answer 2

Given:

number of electron = $10^{6}$

time = 1 sec

To Find:

Current developed

Solution:

we know,

current ( i ) = q / t      {q = charge of the partical,  t = time }

charge on 1 electron = 1.6 * $10^{-19}$C

charge on $10^{6}$ electrons = 1.6 * $10^{-19}$ * $10^{6}$ = 1.6 * $10^{-13}$ C

now,

i = q / t

i = 1.6 * $10^{-13}$ / 1 =

i = 1.6 * $10^{-13}$ C/s = 1.6 * $10^{-13}$ Ampere

So, the current developed is 1.6 * $10^{-13}$ Ampere.