Question

10.6g of sodium cloride reacted with 7.3g of hydrochloric acid producing 11.7 g of sodium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. show that this data varifies the law of conservation of mass​

Answer 1

Correct Question :-

10.6g of sodium carbonate reacted with 7.3g of hydrochloric acid producing 11.7 g of sodium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. show that this data varifies the law of conservation of mass

Required Answer :-

Mass of sodium carbonate = 10.6 g

Mass of Hydrochloric acid = 7.3 g

Mass of sodium chloride (produced) = 11.7 g

Mass of water (produced) = 1.8 g

Mass of carbondioxide gas (produced) = 4.4 g

The given chemical reaction is given by ,

$\cdot\sf \: Na_2CO_3 + 2HCl \longrightarrow 2NaCl + H_2 O + CO_2 \\ \\ \sf \: 10.6g + 7.3 \: g \: \: \: \: \: \: \: 11.7\:g + 1.8 \: g + 4.4 \: g$

Law of conservation of mass states that the total mass of reactants should be equal to the total mass of products.

⇒ 10.6 g + 7.3 g = 11.7 g + 1.8 g + 4.4 g

⇒ 17.9 g = 17.9 g

Hence , The given data verfies the law of conservation of mass.

Answer 2

$\large \sf\underline{ \underline{ \red{correct \: question : }}}$

• 10.6g of sodium carbonate reacted with 7.3g of hydrochloric acid producing 11.7 g of sodium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. show that this data varifies the law of conservation of mass.

$\\ \\ \large \sf\underline{ \underline{ \red{solution : }}}$

Law of censervation of mass :-

• Mass can neither created nor destroyed in chemical reactions. Mass of any element in the beginning(reactant) of reaction is equal to mass of that element at the end(product).

So,

$\\ \boxed{ \mathfrak{mass \: of \: reactan t = mass \: of \: product}}$

$\\ \\ \rm{ Na_{2} CO_{3} + HCl\: \to \: NaCl \: + H_{2}O+ CO_{2} } \\ \small \rm{ \: \: (10.6g) \: \: \: \: \: \: \: \: (7.3g) \: \: \: \: \: \: \: \: (11.7g) \: \: \: \: (1.8g) \: \: \: \: \: (4.4g)}$

We will equate total mass of reactant to total mass of product.

10.6 + 7.3 = 11.7 + 1.8 + 4.4

17.9 = 17.9

$\\ \therefore \sf{mass \: of \:reactant = mass \: of \: product }$

Hence , this data follows law of conservation of mass.