10,7,4.........-62
find last term AP
navdeep98:
full solution
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Answered by
3
Check your question beacuse -62 is only the last term of AP.
d=7-10=-3, a= 10
tn = a +(n-1)-3
-62= 10+(n-1)-3
-72=-3n+3
3n=75
n=25
d=7-10=-3, a= 10
tn = a +(n-1)-3
-62= 10+(n-1)-3
-72=-3n+3
3n=75
n=25
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Answered by
9
10,7,4....-62. is in A.P (Arithmetic progression)
a1 = 10. a2 = 7
d = -3. [d = a2-a1 ]
n = ?
last term of AP (a) is -62
➡(a) = a + (n-1)d
➡-62 = 10 + (n-1)(-3)
➡(n-1)(-3) = -62-10
➡(n-1)(-3) = -72
➡(n-1) = 24
➡n = 25
Hence last term is 25th term of this AP
☺
a1 = 10. a2 = 7
d = -3. [d = a2-a1 ]
n = ?
last term of AP (a) is -62
➡(a) = a + (n-1)d
➡-62 = 10 + (n-1)(-3)
➡(n-1)(-3) = -62-10
➡(n-1)(-3) = -72
➡(n-1) = 24
➡n = 25
Hence last term is 25th term of this AP
☺
(n-1)=24 can you define above line
He divided -72 by -3 which is equal to 24
tq very much
Ohh...I'm sorry ^_^ ^_^ monika
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