Question

10,7,4.......find the 30 term AP​

Answer 1

Answer:

-77

Step-by-step explanation:

Given:

a = 10

d = t(n) - t(n-1)

= t(2) - t(1)

= 7 - 10

d = -3.

We know that,

n th term of an AP [a(n)] = a + (n - 1)d

a(30) = 10 + (30 - 1)(-3)

= 10 + 29(-3)

= 10 - 87

a(30) = -77.

Answer 2

Answer:

• 30th term of AP is -77.

Step-by-step explanation:

Given:

• AP = 10, 7, 4.....
• a = 10
• a₂ = 7

To Find:

• 30th term of AP.

Now, we will calculate common difference, d

=> d = a₂ - a

=> d = 7 - 10

=> d = - 3

Hence common difference = - 3

Now, we know that

aₙ = a + (n - 1)d

a₃₀ = 10 + (30 - 1)-3

a₃₀ = 10 + (29)-3

a₃₀ = 10 - 87

a₃₀ = -77

Hence, 30th term of AP is -77.