- ఒక క్రమ షడ్భుజాకార పట్టకం భూ భుజం 10 సెం.మీ,
దాని
ఎత్తు 8 సెం.మీ. అయిన దాని ఘన పరిమాణం (ఘ. సెం. మీ.)
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Given A regular hexagonal prism with side 10 and height 8
To Find : Volume of the Prism
Solution :
Area of Hexagon = 6 x (√3 / 4) a²
where a is the side of hexagon
Hence area of the hexagon = 6 x (√3 / 4) 10²
= 150√3 sq units
Volume of the prism = Area of hexagon x Height
= 150√3 * 8
= 1200√3 cubic units
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