Question

10,800 for 3 years at 12 1/2 % per annum compounded annualy
(pls do not use SI

Answer 1

★Given:-

• Principal = ₹10800
• Rate = 12.5% per annum
• Time = 3 years

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★To Find:-

• Compound Interest

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★Formula Used:-

▪︎$\bf{Amount = Principal× {(1+ \dfrac{Rate}{100})}^{time}}$

$\bf{▪︎Compound\ Interest = Amount- Principal}$

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★Solution:-

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➥ Finding Amount

$\tt{Amount = Principal×{(1+ \dfrac{Rate}{100})}^{time}}$

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Putting given values in formula:-

$\tt{Amount = 10800 × {(1+ \dfrac{12.5}{100})}^{3}}$

$\tt{= 10800 × {(1 + \dfrac{12.5}{100})}^{3}}$

$\tt{= 10800 × {(1+0.125)}^{3}}$

$\tt{= 10800 × {1.125}^{3}}$

$\tt{=10800 × 1.423828125}$

$\tt{= ₹15377.34375}$

$\boxed{\bf{\purple{\therefore Amount = ₹15377.34375}}}$

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➥ Finding Compound Interest

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$\tt{Compound\ Interest = Amount- Principal}$

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Putting given value in formula:-

$\tt{Compound\ Interest = 15377.34375 - 10800}$

$\tt{Compound\ Interest = ₹4,577.34375}$

$\boxed{\bf{\purple{\therefore Compound\ Interest= ₹4577.35}}}$

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★Answer:-

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Compound Interest on the principal 600 at the rate of 12.5% in 3 years is ₹4577.35.

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Answer 2

$\large\textsf{ }$

$\LARGE\mathfrak{\underline{\underline\textcolor{aqua}{✯\; Given :-}}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Principal ( P ) = ₹ 10,800}$

$\qquad\tt{:}\longrightarrow\large\textsf{Rate Of Interest ( R ) = 12.5 \% p.a. }$

$\qquad\tt{:}\longrightarrow\large\textsf{Time ( n ) = 3 year's}$

$\large\textsf{ }$

$\LARGE\mathfrak{\underline{\underline\textcolor{aqua}{✯\; To \; \; Find :-}}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Compound Interest = ?}$

$\large\textsf{ }$

$\LARGE\mathfrak{\underline{\underline\textcolor{aqua}{✯\; Formula :-}}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{ Amount = P × \left(1 + \cfrac{\large\textsf\textcolor{purple}{R}}{\large\textsf\textcolor{purple}{100}}\right)^{\large\textsf\textcolor{purple}{n}} }}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{C.I. = Amount - Principal }}$

$\large\textsf{ }$

$\LARGE\mathfrak{\underline{\underline\textcolor{aqua}{✯\; Solution :-}}}$

$\large\textsf{ }$

• First we have to calculate the Amount :-

$\large\textsf{ }$

$\qquad\large\textsf{Amount = P × \left(1 + \cfrac{\large\textsf{R}}{\large\textsf{100}}\right)^{\large\textsf{n}} }\\\\\\\qquad\large\textsf{ = 10,800 × \left(1 + \cfrac{\large\textsf{12.5}}{\large\textsf{100}}\right)^{\large\textsf{3}} }\\\\\\\qquad\large\textsf{= 10,800 × ( 1 + 0.125)³}\\\\\\\qquad\large\textsf{= 10,800 × ( 1.125)³}\\\\\\\qquad\large\textsf{= 10,800 × 1.423828125 }\\\\\\\qquad\boxed{\large\textsf\textcolor{red}{∴ Amount = 15,377.34375}}$

$\large\textsf{ }$

• Now let's calculate Compound Interest :-

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Compound Interest = Amount - Principal }\\\\\\\qquad\large\textsf{= 15,377.34375 - 10,800}\\\\\\\qquad\boxed{\large\textsf\textcolor{red}{∴Compound Interest = ₹ 4577.35}}\\\\\\\large\textsf{ }$

∴ The Compound Interest of the given Amount is = ₹ 4577.35

$\large\textsf{ }$