Question

10^9 electrons are removed from the body. What is the charge on the body?

Answer 1

Given ,

The number of electrons (n) = (10)^9

As we know that ,

The charge on a body is an integral multiples of electrons present on it

$\large \boxed{ \sf{Charge \: (q) = ne}}$

Thus ,

q = (10)^9 × 1.6 × (10)^(-19)

q = 1.6 × (10)^(-10) coulomb

$\sf \therefore{ \underline{The \: charge \: on \: a \: body \: is \: 1.6 \times {(10)}^{ - 10} \: coulomb }}$

Answer 2

Answer:

Charge on the body = 1.6×10⁻¹⁰ C

Explanation:

Given that,

Number of electrons removed = n = 10⁹

Charge on 1 electron = e = 1.6×10⁻¹⁹ C

We know that,

Q = ne    where, Q is charge

                           n is number of electrons

                           e is the charge on 1 electron or the basic electronic charge

Putting the values in we get,

Q = ne

Q = 10⁹×1.6×10⁻¹⁹

Q = 1.6×10⁻¹⁰ C