Math, asked by mehreenmuazam60, 9 months ago

10 - 9 sec2A + 9 tan2A =

Answers

Answered by khaathwiksanivada
5

Answer:

9 sec 2A - 9 tan 2A

= 9(sec2A-tan2A)

=9x1

=9

hope this will help u......

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Answered by priya5615
0

Answer:

2sec^A - 1

Step-by-step explanation:

10 - 9sec^A + 9tan^A

10 - 9(sec^A + tan^A)

1(sec^A + sec^A - 1) ( tan^A = sec^A - 1)

1(2sec^A - 1)

2sec^A - 1. Ans

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