10 - 9 sec2A + 9 tan2A =
Answers
Answered by
5
Answer:
9 sec 2A - 9 tan 2A
= 9(sec2A-tan2A)
=9x1
=9
hope this will help u......
plz mark me a brainliest...
Answered by
0
Answer:
2sec^A - 1
Step-by-step explanation:
10 - 9sec^A + 9tan^A
10 - 9(sec^A + tan^A)
1(sec^A + sec^A - 1) ( tan^A = sec^A - 1)
1(2sec^A - 1)
2sec^A - 1. Ans
Similar questions