10. A B and C together can do a piece of work in 8 days. A alone can do it in 20 days,
A and B can do it in 14 days. In how many days will A and C do the same work?
Answers
Answered by
2
Answer:
the answer of the question is C can do work in 12 days
Answered by
6
The work done by A+B+C in one day=1/8
Work done by A in one day. = 1/20
Work done byA+B in one day = 1/14
Work done by C in one day. =1/8 -1/14
(7-4)/56
=3/56
Work by A+c in one day=1/20 +3/56
=(14+15)/280
=29/280
No of days taken by A+c to complete
the work. =280/29
Check:
Work done by C in one day=
A+C work-work byA
29/280 -1/20
(29-14)/280
15/280=3/56 ( work done by C)
(A+B)+C work done
1/14+3/56=(4+3)/56=7/56=1/8
No of days taken by-to complete the work A+B+C =8 (proved)
Work done by A in one day. = 1/20
Work done byA+B in one day = 1/14
Work done by C in one day. =1/8 -1/14
(7-4)/56
=3/56
Work by A+c in one day=1/20 +3/56
=(14+15)/280
=29/280
No of days taken by A+c to complete
the work. =280/29
Check:
Work done by C in one day=
A+C work-work byA
29/280 -1/20
(29-14)/280
15/280=3/56 ( work done by C)
(A+B)+C work done
1/14+3/56=(4+3)/56=7/56=1/8
No of days taken by-to complete the work A+B+C =8 (proved)
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