Question

10.
A batsman deflects a ball by an angle of 90' without changing is install speed, which is equal to 54 h
What is the impulse imparted to the ball ? (Mass of the ball is 0.15 kg)​

Answer 1

Answer have been attached

Answer 2

Given,

Mass of the ball m=0.15kg.

The initial speed of the ball u=

$54km/h= \frac{54×1000}{60 \times 60} =15m/s$

The final speed of the ball vf=ucos45⁰

The momentum change takes place in the ball in the vertical direction only because the initial and final momentum in the horizontal direction is canceled out.

vi =−ucos45⁰

According to the impulse-momentum theorem,

Impulse=Changeinmomentum

$⇒I=m(v_f - v_i)$

$I=mucos45 ^{0} −(−mucos45^0)$

Substitute the value of mass and velocity.

I=2×0.15×15×0.7071

I=3.19kgm/s