Question

10. A battery of 6V is connected in series with resisters of 0.1 ohm, 0.15 ohm.0.2 ohm 0.25 ohm and 6 ohm. How much current would flow through the 0.3 ohm resistor?
(a) 0.895A
(b) 2.22A
(c) 1A
(d) none of these​

Answer 1

Answer: option(D) Non of the above.

Explanation:

Rs=0.1+0.15+0,2+0.25+6

   =6.7 ohm

V=6 v

V=IR

I=V/R

 =6/6.7

 =1.11(approx)

therefore option (D) is correct

Answer 2

The current flow through the 0.3 ohm resistor is 0.895 A.

Explanation:

It is given that,

A battery of 6 V is connected in series with resisters of 0.1 ohm, 0.15 ohm.0.2 ohm 0.25 ohm and 6 ohm. In series combination the equivalent resistance is given by :

$R=R_1+R_2+R_3+....$

$R=0.1+0.15+0.2+0.25+6$

R = 6.7 ohms

Net resistance of the circuit is 6.7 ohms. We need to find the current flowing through the 0.3 ohms resistor.

We know that in series combination, the current through each and every resistor is same. The current flowing through the 0.3 ohms resistor is :

$V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{6\ V}{6.7\ \Omega}$

I = 0.895 A

So, the current flow through the 0.3 ohm resistor is 0.895 A. Hence, this is the required solution.

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