Question

10. A battery of emf 2.5% and internal resistance r is connected in
series with
resistor
of 45s through
an. The ammeter reads
of 50mA. Draw the Eircuit
diagram and calculate the value
of resistance
an ammeter
current
of r. (2017
2015​

Answer 1

Answer:

The ammeter reads current of 50 mA. Draw the circuit diagram and calculate the value of r. ... Current = 50 x 10 -3 A. Emf ... ( 46 + r) ohm = 2.5 V/ 50 x 10 -3 A = 50 ohm