Question

10. A bird is perched on the top of a tree 20 m high and its angle of elevation from a point on the ground is 45°
The bird flies off horizontally straight away from the observer and in 1 sec the angle of elevation of the bird
reduces to 35º. Find the speed of the bird.​

Answer 1

Step-by-step explanation:

bird is perched on the top of a tree 20 m high and its angle of elevation from a point on the ground is 45°

The bird flies off horizontally straight away from the observer and in 1 sec the angle of elevation of the bird

reduces to 35º. Find the speed of the bird.

ANSWER

tan45=1  so height =distance of pole from O=20

Let Bird travels distance x horizontally.

tan30∘=20+x20=31

20+x=203

x=20(3−1)

⇒ Speed is 20(3−1) m/sec

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Answer 2

Step-by-step explanation:

tan45=1 so height =distance of pole from O=20

Let Bird travels distance x horizontally.

tan 30∘ = 20 /20 + x = 1 /√3

=20+x=20 √3

x=20(√3−1)

⇒ Speed is 20(√ 3−1) m/sec