Physics, asked by ashpak263gmailcom, 5 months ago

10) A body executes SHM of time period 8s.If its mass be 0.1kg,its velocity 1s
after it passes through its mean position be 4m/s, find its i)K.E ii) P.E iii) T.E???​

Answers

Answered by nirman95
6

Given:

body executes SHM of time period 8s.If its mass be 0.1kg,its velocity 1 sec after it passes through its mean position be 4m/s.

To find:

  • KE , PE and TE at that point ?

Calculation:

First of all , latest find out the amplitude of the SHM trajectory :

  \therefore \: v = a \omega \cos( \omega t)

 \implies \: 4 = a  \times  \dfrac{2\pi}{T}  \times  \cos( \dfrac{2\pi}{T} \times t )

 \implies \: 4 = a  \times  \dfrac{2\pi}{8}  \times  \cos( \dfrac{2\pi}{8} \times 1 )

 \implies \: 4 = a  \times  \dfrac{\pi}{4}  \times  \cos( \dfrac{\pi}{4}  )

 \implies \: 4 = a  \times  \dfrac{\pi}{4}  \times  \dfrac{1}{ \sqrt{2} }

 \implies \: a   =  \dfrac{16 \sqrt{2} }{\pi}  \: m

 \implies \: a    \approx \: 7.2 \: m

Now, displacement from the mean position at the time be "x" :

 \therefore \: x = a \sin( \omega t)

 \implies \: x =  \dfrac{16 \sqrt{2} }{\pi} \times  \sin( \dfrac{2\pi}{8}  \times 1)

 \implies \: x =  \dfrac{16 \sqrt{2} }{\pi}  \times  \sin( \dfrac{\pi}{4} )

 \implies \: x =  \dfrac{16 \sqrt{2} }{\pi} \times  \dfrac{1}{ \sqrt{2} }

 \implies \: x = 5.09 \: m

Now, let potential energy be PE :

 \therefore \: PE =  \dfrac{1}{2} m  { \omega}^{2} {x}^{2}

 \implies \: PE =  \dfrac{1}{2}  \times 0.1 \times  {( \dfrac{\pi}{4}) }^{2} \times  {(5.09)}^{2}

 \implies \: PE =  \dfrac{1}{2}  \times 0.1 \times   \dfrac{ {\pi}^{2} }{16} \times  25.9

 \implies \: PE = 0.08 \times  {\pi}^{2}

 \boxed{ \implies \: PE = 0.78 \: J}

Now, kinetic energy be KE :

 \therefore \: KE =  \dfrac{1}{2} m  { \omega}^{2} ( {a}^{2}  - {x}^{2} )

 \implies \: KE =  \dfrac{1}{2} \times 0.1 \times \dfrac{ {\pi}^{2} }{16}    \times \{{(7.9)}^{2}  -  {(5.9)}^{2}  \}

 \implies \: KE =  \dfrac{1}{2} \times 0.1 \times  \dfrac{ {\pi}^{2} }{16} \times   27.6

 \boxed{ \implies \: KE = 0.86 \: joule}

So, total energy :

 \boxed{ \therefore \: TE = 0.86 + 0.78 = 1.64 \: joule}

Answered by Anonymous
3

Explanation:

Qᴜᴇꜱᴛɪᴏɴ⤵

10) A body executes SHM of time period 8s. If its mass be 0.1kg, its velocity Is after it passes through its mean position be 4m/s, find its

K.E

P.E

T.E??

ᴀɴꜱᴡᴇʀ⤵

1.ᴋᴇ✔

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