10. A body of mass 5 kg is at rest on a
smooth horizontal surface. A horizontal
force 'F' acts on it for 4s and then ceases to
act. If the body travels 40 m in the next 5s,
the value of F is,
1) 5 N 2) 20 N 3) 15 N 4) 10 N
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Answer:
Now... F=5.a
a=f/5 so. V=0+f/5.4
V=4F/5
NOW........ 40=4F/5.5
SO F=10N
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