Question

10. A cake weighing 1.98 kg is cut into two parts so that the first part is heavier than the second by 20%. Find the
weight of each part.
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Answer 1

weight of the cake = 1.98 kg or 1980 gram

$let \: , \:$

$\implies$ first part be = x

$\implies$ second part be = x + 20

$\therefore$ A/Q ,

$\implies$ x + x + 20 = 1980

$\implies$ 2x = 1980 - 20

$\implies$ x = $\frac{1960}{2}$

$\implies$ x = 980

$\therefore$

$\implies$ first part , x = 980

$\implies$ second part , x + 20 = $980\:+\:20 \\ 1000$

Answer 2

Step-by-step explanation:

weight of the cake = 1.98 kg or 1980 gram

let \: , \:let,

\implies⟹ first part be = x

\implies⟹ second part be = x + 20

\therefore∴ A/Q ,

\implies⟹ x + x + 20 = 1980

\implies⟹ 2x = 1980 - 20

\implies⟹ x = \frac{1960}{2}

2

1960

\implies⟹ x = 980

\therefore∴

\implies⟹ first part , x = 980

\implies⟹ second part , x + 20 = \begin{gathered} 980\:+\:20 \\ 1000 \end{gathered}

980+20

1000