Question

10. A can do a piece of work in 80 days. He works at it for 10 days and then B alone
remaining work in 42 days. In how many days could both do it?
11. A and B can together fininh
en B alone finishes​

Answer 1

Answer:

.[10.]30 days

Step-by-step explanation:

[.10.]A’s Efficiency = 1/80

A works for 10 days therefor completed work by A = 10* (1/80) =10/80 = 1/8

Remaining work = 1-(1/8) = 7/8

B completed the remaining job in 42 days

Therefor B alone can complete the job in =

(7/8) /1/b = 42 , b is the efficiency of B

(7/8 )*b = 42

b= 42*8/7 =48

Efficiency of B = 1/48

Therefor A & B can complete the work in = (1/80) + (1/48)

= 1/30 They can complete the work in 30 days

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