10. A can do a piece of work in 80 days. He works at it for 10 days and then B alone finishes the
remaining work in 42 days. In how many days could both do it?
Answers
Answered by
5
Answer:
A's 1 days' work =
80
1
A's 10 days' work =
80
10
=
8
1
Remaining work =1−
8
1
=
8
7
8
7
of the work is completed by B in 42 days
∴ The whole work is completed by B in
7
42×8
days = 48 days
∴ B's 1 days' work =
48
1
(A + B)'s 1 days' work =
80
1
+
48
1
=
240
3+5
=
240
8
=
30
1
∴ A and B can complete the whole work together in 30 days
Step-by-step explanation:
Answered by
1
Answer:
52 days
Step-by-step explanation:
a works for 10 days and b works for 42 days so the answer is 52
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