Question

10. A car 2 in long and 3m wide is moving at 10 m/s when a
bullet hits kin a direction making mangle of an
with the car as seen from the ground. The bullet enters
one edge of the car at the corner and passes out at
diagonally opposite comer. Neglecting gravity, the time
for the bullet to cross the car is
​

Answer 1

Answer:

6 seconds with the car as seen from the ground. The bullet enters

one edge of the car at the corner and passes out at

diagonally opposite comer. Neglecting

Answer 2

Given:

Length of car = 2m

Width of car = 3m

Speed of car = 10m/s

To find:

The time taken for the bullet to cross the car

Solution:

• We know that speed = Distance/ time taken
• ⇒Time taken = Distance/ speed.    -(1)
• Distance = diagonal of the car
• Assuming the car to be a rectangle, by Pythagoras theorem -
• Diagonal of car = √(2² + 3²)
• Diagonal = √13
• From equation 1 -
• Time taken = √13/ 10 = 0.36 sec

The time taken for the bullet to cross the car = 0.36 sec