Question

10. A car of mass 1000kg is moving at a certain speed when a constant braking force 1000N acts on it for 5sec and speed of the car reduced to half the original speed. Find the further time required to stop the car if the same constant force acts on it.

Answer 1

Answer:

5s

Explanation:

The braking force of 1000N for 5s will give a decrease in momentum equal to 5000 kg m/s.

Given that after this the car was left with half the original speed means that if x was the original speed then :

1000kg*x - 5000 kg m/s = 1000kg*(x/2)

Solving the equation, we will get x = 10 m/s

And x/2 = 5m/s

Now, if the same force is applied again, let time taken for object to come to a stop = t

So,

$t = \frac{1000kg \times 5m {s}^{ - 1} }{1000 \: kg \: m {s}^{ - 2} }$

= 5s

Answer 2

Answer:

refer to the attachment above for ur answer

Explanation:

hope it helps you ^_^

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