Question

10. A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a with
speed of 50 km/h. Find
(1) displacement of the car
(1) distance travelled by the car.
() average speed of the car​

Answer 1

Answer:

average speed =2*30*50/80=37.5

Answer 2

since the initial position and final position is same ,so displacement of the car is 0.

Let the distance travelled by the car From A to B =x KM

so,car travels From A to B and then returns to A so therefore total distance travelled= 2x KM

Time taken to reach B from A= distance/speed =( x/30 )h

similarly,time taken to reach back A from B=( x/50) h

therefore total time taken= x/30+x/50=(4x/75)

h

so average speed = total distance/total time taken

=( 2x*75)/4x =37.5 KM/h

and total distance= 2x=2*37.5=75 KM