Question

10. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of
the head. It bounces back up 1.50 m before falling to the ground. If the mass of the coconut is
2.00 kg, calculate the potential energy of the coconut relative to the ground at each of the following
sites:
(a) while it is still in the tree,
(b) when it hits the bystander on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole.​

Answer 1

Answer:

Answer:The work done by porter on the luggage​ is 225 JExplanation:Given,A porter lifts a luggage of mass = 15 kg from the ground.It's on his head 1.5 m above the ground.To find: The work done by him on the luggage​Solution:here, Force is due to the weight of the luggage.i.e F = mg , where m = mass of luggage and g = accerleration due to gravityor, F = 15 * 10 = 150 NWork done can be given as:W = F * swhere, F = force and s = displacement i.e 1.5 mW = 150 * 1.5 = 225 JTherefore, The work done by porter on the luggage​ is 225 J.Answer:The work done by porter on the luggage​ is 225 JExplanation:Given,A porter lifts a luggage of mass = 15 kg from the ground.It's on his head 1.5 m above the ground.To find: The work done by him on the luggage​Solution:here, Force is due to the weight of the luggage.i.e F = mg , where m = mass of luggage and g = accerleration due to gravityor, F = 15 * 10 = 150 NWork done can be given as:W = F * swhere, F = force and s = displacement i.e 1.5 mW = 150 * 1.5 = 225 JTherefore, The work done by porter on the luggage​ is 225 J.

Explanation: