Question

10. A courtyard 25.5 m long and 16 m board is to be paved with bricks of length 34 cm and breadth 20 cm. Find the number of bricks required.

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Answer 1

Answer:

$\maltese\LARGE\textsf\textcolor{aqua}{\underline{Solution:-}}$

$\LARGE\sf\green{No.\:of\:bricks\:required\:=}$

$\LARGE\sf\red{60,000\:bricks}$

Step-by-step explanation:

GIVEN :-

A courtyard 25.5 m long and 16 m board is to be paved with bricks of length 34 cm and breadth 20 cm

TO FIND :-

the number of bricks required.

SOLUTION :-

AS WE CAN SEE THAT THE MEASUREMENT OF COURTYARD IS IN METRES.

BUT THE MEASUREMENT OF BRICK ARE IN CENTIMETRE.

So, convert metres into centimetres.

New Length :-

➝$\sf{25.5\:\times\:100}$

➝2550 cm

New Breadth :-

➝$\sf{16\:\times\:100}$

➝1600 cm

TO FIND, the no. of bricks first obtain their areas.

Area of courtyard will be,

$\sf{Area\:of\:rectangle\:=\:L\:\times\:B}$

➝$\sf{2550\:\times\:1600}$

➝$\sf{4080000}$

SIMILARLY,

Find the area of brick.

$\sf{Area\:of\:rectangle\:=\:L\:\times\:B}$

➝$\sf{34\:\times\:20}$

➝$\sf{680}$

NOW,

THE NO. OF BRICKS =

➝$\sf{\LARGE\dfrac{408000\cancel{0}}{68\cancel{0}}}$

➝$\sf{\LARGE\dfrac{\cancel{408000}}{\cancel{68}}60,000}$

$\sf\green{The\:of\:bricks\:required\:=\:60,000}$

$\Large\mathcal\pink{Hope \: it \: helps \: you\:friend}$