Question

10. A cricket ball of mass 150 g moving at a speed of
25 ms-1 is brought to rest by a player in
0-03 s. Find the average force applied by the
player.





If the answer is wrong, it will be reported.




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Answer 1

Answer:

Mass, m = 150g = 0.15kg

Speed, v = 25m/s

Time, t = 0.03sec

So

=> F = ma

To find a (acceleration) we use

=> a = v/t

=> a = 25/0.03

=> a = 833.34 $m/{s}^2$

Now to find Force we use

=> F = ma

=> F = 0.15kg × 833.34$m/{s}^2$

=> F = 125N

Answer 2

Answer:

-125N

Explanation:

V=U+at

0=25+a(0.03)

a=-2500/3m/s2

F=ma=0.15kgx-2500/3

F=-125N

Hope it helps u....