Question

10. A current of 1 A is drawn by a filament of an electric bulb. The number of electrons passing
through the cross section of filament in 16 sec is*
(1 Point)
AO 1 x 1020
BO 2x 1020
CO 1 x 10-20
D0 1 x 1022​

Answer 1

Answer:

Hence, number of electrons passing through a cross section of the filament in 16 seconds would be roughly 1020.

Explanation:

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Answer 2

Answer:

I = Q/t

Q= It

Q= 1* 16

Q= 16 q

Q=ne

n = Q/e

n = 16 /1.6 * 10 ^ -19

n = 10 * 10^ 19

n = 10 ^ 20 electrons

The number of electrons flowing is 10 ^ 20 electrons

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