Question

10. A die is thrown twice. Find the probability of getting “3 will come up at least once"..

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Answer 1

Total no. of outcomes = 12 (since the dice is thrown twice there will be 6+6=12 outcomes)

${\boxed{\bf{{Probability}=\frac{Total \: no. \: of \: possible \: outcomes}{Total \: no. \: of \: outcomes}}}}$

Probability (3 will come up at least once) = $\frac{2}{12}$, i.e. $\frac{1}{6}$