Question

10. (a) Estimate the fall in the height of the mercury column when the barometer is taken from sea level to a hill top of altitude 1.0 km. For
this rough estimate take the density of mercury to be 13000 kg m-3 and the density of air to be 1.3 kg m-3. Assume the densities
remain the same at such low altitude. (b) If the barometer reading at sea level is 760 mm of mercury, what is the reading at the hill
(Ans. 10 cm, 560 mm)
top?​

Answer 1

Answer:

Pressure differences between sea level and the top of hill

△p=(h

1

−h

2

)×p

Hg

×g

=(75−50)×10

−2

×p

Hg

×g ...(i)

and pressure difference due to h metre of air

△p=h×p

air

×g ...(ii)

By equating Eqs. (i) and (ii)

h×p

air

×g

=(75−50)×10

−2

×p

Hg

×p

p=25×10

−2

(

p

air

p

Hg

)

=25×10

−2

×10

4

=2500m

∴ Height of hill = 2.5 km

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