Question

10. A farmer had fodder for 40 animals for 60
days. He bought some more animals and the
fodder lasted for 50 days. How many animals
did he buy?​

Answer 1

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Let the food will now last for x days. Then,

Number of animals 20 30

Number of days 6 x

Clearly, more is the number of animals, less will be the number of days for food to last.

So, it is a case inverse proportion.

$20  ×  6 = 30x  ⇒  x = \frac{20 \times 6}{30} = 4</p><p></p><p>$

Hence, the food will now last for 4 days.

Answer 2

Answer:

let the total number . of answer in final be X

the equation formed of the answer is 40 ×60×=5×x

on solving the equation will be gate X as 48

hence ,no . of animals the farmer bought

=48-49

=8.