Question

10
A farmer movere along the boundaru
What will be the meegritude of
of o esquare field of silde Tom in 40s.
displacement of the former at the
end of 2 menetes 20 sec for from
n his
initial position​

Answer 1

Answer:

Given, side of the square field = 10 m

Therefore, perimeter = 10×4 = 40 m

Farmer moves along the boundary in 40 s.

Total time of journey = 2×60+20 = 140 s

Since, in 40 s farmer moves 40 m.

Therefore, in 1 s distance covered by farmer = 40/40 m = 1 m

Therefore, in 140 s distance covered by farmer = 10×4 = 40 m

Now,

Number of rotation to cover 140 along the boundary

= (total distance)/(Perimeter)

= 140/40 = 3.5 m

Thus, after 3.5 round farmer will at point C of the field.

Therefore displacement

(AC)² = (10)² + (10)²

(AC)² = 100+100

(

(AC)² = 200

AC = √200

AC = 14.143 m

Thus, after 2 minutes 20 seconds the displacement of farmer will be equal to 14.143 m north east.

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