*10.
A force of 50 N acts on the block at the angle shown in the diagram. The block me
distance of 3.0 m. Then the work done by this force
30°
Surface
(A)130.51
(C)125J
(B) 129.9 J
(D) 128.75 J
Answers
Answered by
3
Given:
A force of 50 N acts on the block at the angle shown in the diagram. The block me distance of 3.0 m. 30°Surface
(A)130.51
(C)125J
(B) 129.9 J
(D) 128.75 J
To find:
The work done by this force
Solution:
From given, we have,
A force of 50 N acts on the block at the angle shown in the diagram. The block me the distance of 3.0 m. 30°Surface
W = Fd cos ∅
W = 50 × 3 × cos 30
W = 150 × √3/2
W = 75√3
W = 129.9 J
Option (B) 129.9 J is correct
Similar questions